| paper | d4-conf-aaai-2010-0117 |
| authors | — |
| venue | ? |
| filed under | unclassified |
| judged by | gpt-6-luna / xhigh (triple__luna__xhigh__c6r1) |
| judge confidence | high |
| authors would recognise it | yes |
The continuous Plurality question is coherent, and the finite-rule limit addresses the zero-mass incentive issue. But Theorem 3 bounds the quality of strategyproof rules; it does not analyze the computation of an outcome or the complexity of a problem. That leaves the proposed anchor without the computational character required for a ChoCo mirror.
fails bit a — no named computational result to mirror
The proposed question concerns Plurality approximation under strategyproofness; it does not mirror the paper's other scoring-rule, Copeland, or Maximin results.
The strongest mirror I can defend is narrow: take an election with many voters but relatively few distinct rankings, and represent it by the fraction of voters holding each ranking. For example, a large membership election may have millions of voters but ballots drawn from a small recurring set. A type is a complete ranking \(t\in L(A)\); its mass \(\mu_t\) is its share of the electorate.
My closest named anchor is Theorem 3, proved in this paper, with its proof relegated to the full version. It states that no strategyproof randomized voting rule can approximate Plurality to a factor of \(\omega(1/\sqrt m)\). That is, as the number \(m\) of alternatives grows, no such rule guarantees a factor asymptotically larger than \(1/\sqrt m\).
Here is the continuous question I would hand to a prover:
High-Multiplicity Continuous Plurality Approximation under Strategyproofness. The target is an alternative set \(A\), with \(|A|=m\), and the domain is every society \(\mu\in\Delta(L(A))\). Define the per-capita Plurality score
\[
p_\mu(a)=\sum_{t:\,a\text{ is ranked first in }t}\mu_t.
\]
Find the largest guarantee \(\gamma_m\) for which there is a lottery rule \(\Phi:\Delta(L(A))\to\Delta(A)\) satisfying
\[
\sum_{a\in A}\Phi(a\mid\mu)\,p_\mu(a)
\ge \gamma_m\max_{a\in A}p_\mu(a)
\]
for every \(\mu\) with positive optimal score.
To keep strategyproofness meaningful, count \(\Phi\) as admissible only if it is a limit of anonymous, strategyproof \(N\)-voter rules: whenever empirical distributions \(\mu_N\) converge to \(\mu\), the corresponding lotteries converge to \(\Phi(\cdot\mid\mu)\). A solution is an admissible rule and its guarantee, or an upper-bound proof ruling out a larger guarantee. The question is whether the \(O(1/\sqrt m)\) impossibility in Theorem 3 survives this high-multiplicity limit.
I expect the finite result to transfer if its bound holds uniformly for the growing electorates used in the limit. In the programme’s three-way vocabulary, this is closest to hardness transferring: the desired negative bound comes from the finite strategic restriction on rules, and the mirror should reproduce it. That label is only an analogy here; the result is not a complexity-hardness theorem.
The fit has a clear limit. The paper’s numbered Theorems 2–8 give approximation guarantees for strategyproof mechanisms. Its introduction explicitly distinguishes this from computational approximation of hard-to-compute voting rules. It supplies no named classification of running time or computational hardness of bribery, control, campaigning, or robustness. So the proposed question is a coherent continuous version of the paper’s mechanism-design objective, but it is not a strong ChoCo computational anchor.
My weakest point is the incentive model. In a strictly atomless society, one voter has zero mass, so individual strategyproofness becomes vacuous for rules depending only on aggregate masses. The finite-rule lift preserves the paper’s incentive condition, but also retains finite-resolution strategic effects. The theorem’s stated voter-count quantification must be checked before claiming its bound survives when each type has many copies.
Theorem 3 is a real result about strategyproof mechanism design, but it gives no computational result to continuize. It bounds the approximation ratio achievable by strategyproof lotteries; it does not analyze the time or complexity of computing a manipulation, intervention, or winner. The paper itself distinguishes its goal—using approximation to obtain strategyproofness—from computational approximation of hard-to-compute rules. [Procaccia’s paper](https://ojs.aaai.org/index.php/AAAI/article/view/7619) So the proposed Plurality question may be coherent, but it is not a computational mirror in ChoCo’s sense.
The mass version makes that distinction clear. Given \(\mu\), calculating \(p_\mu(a)\) is a direct sum over the supported rankings. The hard question is how good a strategyproof lottery rule can be over all societies. That is a worst-case mechanism-design guarantee, not an algorithmic question about an input society. Turning the guarantee into a computational problem would require adding a representation and computation model for the mechanism—work the paper does not supply.
There is also a genuine incentive-model gap. If the rule sees only an atomless distribution \(\mu\), one voter’s lie changes no mass, so individual strategyproofness is vacuous. The proposed limit of anonymous strategyproof \(N\)-voter rules is the strongest repair: it preserves finite-agent incentives and asks about their high-multiplicity limit. Even granting that Theorem 3’s bound transfers to this limit, the result would still concern asymptotic mechanism design, not computational complexity. Treating a positive-mass type as a strategic actor would avoid the zero-mass issue by changing the requirement to group strategyproofness, which is a different problem.
So the strongest case against this anchor is about fit, not whether the continuous question is mathematically sensible or what its answer might be. I cannot honestly establish the universal claim that no scenario could make this line of work worthwhile: the asymptotic mechanism-design question could be worthwhile in its own right. But changing the scenario or type space does not turn Theorem 3 into a computational result. For the ChoCo programme, that is a substantial reason to reject this mirror.
The adversarial triple: the proponent anchors on up to three named results; the opponent sees that case and must defeat every anchor; the judge decides which case convinced it. These are the pipeline’s own outputs, generated by tools/triple_run.py — no human edited them. The paper’s own text is not reproduced here beyond the quoted statement above.