d4-conf-atal-2015-0056

· ? (d4-conf-atal-2015-0056)

mirror foundnew result: P → P — proved & adversarially reviewed →
paperd4-conf-atal-2015-0056
authors—
venue?
filed underunclassified
judged bygpt-6-luna / xhigh (triple__luna__xhigh__c6r1)
judge confidencehigh
authors would recognise ityes

The new result

P→P discrete result → its continuous mirror

Answer: The problem is in \(\mathrm P\) for every fixed rational \(\alpha\in[0,1)\), with running time \(O((\tau+1)m^2L^2)\) in bit operations. · discrete side: polynomial · adjudication: proved

full proof & adversarial review →

The anchor — algorithmic

Theorem 4

PDF text-layer excerpt — equations and symbol order may be approximateThe weighted manipulation problem for Copelandα is polynomial-time solvable in single-peaked elections, for every 0 ≤α < 1. PROOF. We first give the proof for the unique-winner model with three candidates. To this end, we derive a polynomial-time algorithm. First observe that ranking the distinguished candidate p in the top is always the optimal choice.

statement extracted from the paper’s text layer

Every anchor argued

The continuous mirror question

Given candidates \(C\), a known left-to-right order \(L\), a target \(p\), a fixed rational \(\alpha\in[0,1)\), a rational mass distribution over nonmanipulator rankings that are single-peaked with respect to \(L\), and a strategic bloc of mass \(\beta\), does there exist an allocation of that bloc among \(L\)-single-peaked rankings that makes \(p\) a Copeland\(_\alpha\) co-winner?

The model it lives in

Types are complete rankings single-peaked with respect to \(L\); the nonmanipulators have rational masses \(\mu_i\), and the strategic bloc has total mass \(\beta\). Choose report masses \(x_\sigma\geq0\) summing to \(\beta\); pairwise masses determine wins and ties, and the objective is feasibility: make \(p\) a co-winner.

What the mirror covers

The mirror covers Theorem 4: weighted Copeland\(_\alpha\) manipulation for fixed \(0\leq\alpha<1\) under strict single-peakedness. It leaves Theorems 1–3 and the paper's other results unmirrored.

Open questions for a prover

The case FOR (proponent)

The strongest case I see is a mass-valued version of the paper’s weighted Copeland result.

Theorem 4, proved in this paper, says that for every fixed \(0\leq\alpha<1\), weighted manipulation under Copeland\(_\alpha\) is polynomial-time solvable in single-peaked elections, without bounding the number of candidates or manipulators. Voters have nonnegative integer weights, and the result holds in both the unique-winner and non-unique-winner models. The hardness results in the paper’s tables are credited to earlier work, rather than stated as numbered results proved here, so I would not use them as anchors.

Here is the continuous problem I would hand to a prover. Fix candidates \(C\), a target \(p\), a known left-to-right order \(L\), and a fixed rational \(\alpha\in[0,1)\). The nonmanipulating society is given by a support list of single-peaked rankings \(\succ_i\), each with rational mass \(\mu_i\). A strategic bloc has mass \(\beta\), with \(\sum_i\mu_i+\beta=1\). The bloc shares a target \(p\), sincere type, voting rights, and the same set of permitted reports: all rankings single-peaked with respect to \(L\). Choose rational masses \(x_\sigma\geq 0\), one for each permitted report \(\sigma\), with \(\sum_\sigma x_\sigma=\beta\). For each pair \(a,b\), compute
\[ Q(a,b)=\sum_i \mu_i\,\mathbf 1[a\succ_i b]+\sum_\sigma x_\sigma\,\mathbf 1[a\succ_\sigma b]. \]
The question is whether an allocation \(x\) makes \(p\) a Copeland\(_\alpha\) co-winner, using \(Q(a,b)>Q(b,a)\) for a win and equality for a tie. A solution is the allocation of the bloc’s mass among its permitted reports; it can be given as a sparse list of positive-mass reports.

This has a plausible high-multiplicity regime: a large election or organization-wide poll with a known left-right issue axis, many voters but relatively few distinct rankings, and a sizable coordinated bloc. The bloc might be party or union members following a common endorsement. Its size is meaningfully described as a fraction \(\beta\); its members share a type and objective, while the rest of society is represented by masses \(\mu_i\). That keeps the paper’s manipulation question intact: the decision is still whether strategic voters can make \(p\) win, and their reports obey the same single-peaked restriction.

I expect this mirror to be Class A, tractable. The bridge is unusually direct. Clear the rational denominators to obtain integer voter weights; scaling all weights by the same positive factor preserves every pairwise win and tie. If a successful continuous strategy splits the bloc among reports, the paper’s proof of Theorem 4 gives a successful strategy in which all manipulators use one common report. Thus the mass allocation can be replaced by putting all \(\beta\) on that report. The theorem’s weighted-median structure extends to rational masses, and its algorithm is polynomial in the candidate count, support size, and mass bit length.

The scope is only Theorem 4: strict single-peakedness and weighted Copeland\(_\alpha\) for \(\alpha<1\). This does not mirror Theorems 1–3 on bounded single-peaked width, Borda, or Maximin. A natural next question is whether the same mass formulation remains tractable when the known domain is widened to single-peaked width \(k>1\).

The soft spot is also clear: this continuous question is very close to the paper’s integer-weighted problem, and denominator scaling plus Theorem 4 largely settles it. That makes it a modest mirror rather than a new complexity frontier. Still, the paper gives a concrete, recognizable continuous-population question, and the fact that its answer is tractable is a meaningful bridge from weighted electorates to rational mass distributions.

The case AGAINST (opponent, writing after the proponent)

The strongest case against this anchor is that its proposed continuum is almost exactly the paper’s weighted problem after normalization. Given rational masses, clear denominators to obtain integer weights; every pairwise win and tie is preserved. Theorem 4 already handles those weights, and its proof lets the manipulators use one common report, so allowing the strategic mass to split across reports adds no power. A version with arbitrary real masses would need a different input model to make exact computational complexity meaningful; rational masses return us to the weighted instance.

That makes this a low-novelty mirror. But it does not defeat it under the programme’s stated standard: weighted and high-multiplicity work supports the plausibility of a continuous population, and an exact discrete-to-continuous identity can itself be a worthwhile result. Theorem 4 is a named computational result, and a large electorate with repeated single-peaked rankings and a coordinated bloc is a sensible high-multiplicity regime. I can argue that this mirror offers little new algorithmic terrain; I cannot honestly argue that no worthwhile mirror survives. The proposed anchor is likely to hold.

The adversarial triple: the proponent anchors on up to three named results; the opponent sees that case and must defeat every anchor; the judge decides which case convinced it. These are the pipeline’s own outputs, generated by tools/triple_run.py — no human edited them. The paper’s own text is not reproduced here beyond the quoted statement above.