d4-conf-atal-2017-0263

· ? (d4-conf-atal-2017-0263)

mirror foundnew result: P → P — proved & adversarially reviewed →
paperd4-conf-atal-2017-0263
authors—
venue?
filed underunclassified
judged bygpt-6-luna / xhigh (triple__luna__xhigh__c6r1)
judge confidencehigh
authors would recognise ityes

The new result

P→P discrete result → its continuous mirror

Answer: Exact computation of \(BR_c\) is polynomial-time solvable in \(m,\tau,L\). · discrete side: polynomial · adjudication: proved

full proof & adversarial review →

The anchor — algorithmic

Proposition 1

PDF text-layer excerpt — equations and symbol order may be approximateLet F be a voting rule, computable in O(Tn,m) time for any preference profile of n voters over m candidates, where Tn,m is some function of n and m. Let V = Vlex be the lexico- graphically tie-broken version of F. Then for any candidate c ∈C, the best response set, Bc(s−c), is computable in O(n · m · [Tn,m + log(m)]). In particular, if T is a polynomial function, then computing Bc(p, s) can be done in polynomial time.

statement extracted from the paper’s text layer

Every anchor argued

The continuous mirror question

Given \(m\) candidates, rational ideal points \(q_t\) with positive rational masses \(\mu_t\) summing to \(1\), fixed positions of all candidates except \(c\), a rational interval \(I_c\), a fixed rational positional scoring rule, and \(c\)'s preference order over winners, compute exactly the set \(BR_c=\{x\in I_c: W(x)\succeq_c W(y)\text{ for every }y\in I_c\}\). Each type ranks candidates by distance from \(q_t\), ties are resolved by the fixed lexicographic order, scores are weighted by \(\mu_t\), and election ties are resolved by that same order; represent \(BR_c\) as intervals and individual breakpoint positions.

The model it lives in

A finite set of strategic candidates faces a voter society given by a distribution \(\mu\) over ideal-point types \(q_t\). Each type has mass \(\mu_t\), ranks candidates by distance with lexicographic tie-breaking, and contributes its mass to the scoring rule; one candidate chooses a position \(x\) while the others’ positions are fixed.

What the mirror covers

Covers Proposition 1’s best-response computation for a fixed positional scoring rule; leaves the equilibrium existence and nonexistence results untouched.

Open questions for a prover

The case FOR (proponent)

My lead mirror is Mass-RCG Best Response, anchored in Proposition 1, proved in this paper. Proposition 1 says that for a lexicographically tie-broken voting rule \(V=V_{\mathrm{lex}}\), if the underlying rule \(F\) can compute an outcome on \(n\) voters and \(m\) candidates in time \(O(T_{n,m})\), then, for any candidate and fixed positions of the other candidates, the candidate’s full best-response set can be computed in \(O(nm[T_{n,m}+\log m])\). Thus best responses are polynomial-time computable whenever \(F\) is. This is an algorithmic anchor, not a hardness result; the paper’s numbered equilibrium existence and nonexistence propositions are not computational-complexity results.

In the mirror, a voter type is an ideal point \(q_t\) on the paper’s political axis. A society is a finite-support distribution \(\mu\): each rational mass \(\mu_t\) is the fraction of the electorate at \(q_t\), and \(\sum_t\mu_t=1\). Suppose there are \(m\) candidates, the other candidates’ positions are fixed, and candidate \(c\) may choose any position \(x\) in a rational interval \(I_c\). Each type ranks candidates by distance from its ideal point, resolving equal distances by the paper’s fixed lexicographic order. Use a fixed rational positional scoring rule, with the election winner also selected lexicographically among candidates tied for highest score. Candidate \(c\) retains its preference order \(\succ_c\) over winners.

The problem asks for the set
\[ BR_c=\{x\in I_c: W(x)\succeq_c W(y)\text{ for every }y\in I_c\}, \]
where \(W(x)\) is the winning candidate when \(c\) chooses \(x\). Represent the answer as a union of intervals and individual breakpoint positions, so the full best-response set is specified exactly. This is the underlying strategic positioning problem from the paper; it does not ask the prover to compute an encoding.

A plausible regime is a large primary or party election with many voters concentrated at a modest number \(\tau\) of shared ideological positions. For example, millions of voters might belong to a few dozen stable platform groups. The type is the ideal point that determines all voter preferences used by the model; mass is the group’s share of the electorate. The number of people can greatly exceed \(\tau\), while candidates still choose positions continuously and retain their possibly non-selfish preferences over election winners.

I expect this mirror to be tractable (Class A). As \(c\) moves, a type’s ranking can change only at positions where \(c\) ties an opponent in distance. With \(\tau\) types and \(m\) candidates, these points partition \(I_c\) into polynomially many cells. Within each cell the weighted preference profile and winner are constant. Evaluating each cell and its boundary points therefore gives an exact polynomial-time algorithm in \(m,\tau\), and the rational input bit length \(L\). This adapts Proposition 1’s breakpoint idea to mass input; it is not a claim that the paper already proved this mass version. It also gives a useful high-multiplicity input measure: the computation can depend on the number of distinct ideal points rather than the electorate size.

The scope is deliberately narrow: this mirrors Proposition 1’s best-response computation, not the paper’s Nash-equilibrium existence results. It raises follow-up questions about the formal relationship between mass best responses and finite profiles with proportions \(n_t/n\), about richer representations such as piecewise-constant ideal-point densities, and about whether pure equilibria can be computed in the mass model. The last question connects to a direction the paper itself leaves open.

The weakest point is that the paper explicitly builds on Hotelling–Downs, whose voter distribution is already non-atomic. A plurality version of this proposal would sit especially close to that prior model. The distinction here is that the paper’s formal RCG input is still a finite vector of \(n\) voter positions, while this question combines a population measure with strategic candidates, their preferences over winners, and scoring-rule best responses. The paper itself observes that non-atomic Hotelling–Downs models had been limited to particular voting-rule variants, whereas RCGs permit broader rules. That makes this a credible mirror of the paper’s formal computational question, though a modest one: its strongest contribution is the population-based input and parameterization, not a predicted dissolution of discrete hardness.

The case AGAINST (opponent, writing after the proponent)

The strongest case against the Mass-RCG Best Response mirror is that Proposition 1’s computation is driven by a one-dimensional breakpoint sweep, not by population multiplicity. For a finite-support society with ideal points \(q_t\) and fixed opponent positions \(y_j\), type \(t\)’s ranking can change only when the moving candidate reaches \(x=2q_t-y_j\). These \(O(\tau m)\) thresholds divide the strategy interval into cells where every type’s ranking, every weighted score, and the winner are fixed; evaluate the cells and threshold points, and the exact best-response set follows. That makes the proposed mirror faithful, but it also makes it look like a compressed implementation of the paper’s finite-profile argument.

There is some nearby continuous-population computation: a recent Hotelling–Downs paper gives equilibrium algorithms for continuous or discrete voter distributions and candidate positions. But it studies the basic model where candidates maximize vote share, not RCGs with general voting rules and preferences over winners, so it does not settle this mirror. [The paper](https://arxiv.org/abs/2412.12523)

That leaves the negative case resting on priority: in generic spatial instances, distinct voter positions can make \(\tau=n\), while a small \(\tau\) assumes repeated ideal points. A model with a genuine continuous density instead changes the input representation and moves toward the familiar Hotelling–Downs setting. These points narrow the mirror’s reach, but they do not defeat it under ChoCo’s standards. A large electorate with a few shared ideological types is plausible; ideal point is a complete type for this model; and mass scores preserve the election outcome and the candidates’ preferences. Existing Hotelling–Downs work is not a computational treatment of this RCG question.

So the honest negative case is weak. Proposition 1 is a named computational result, and the mass version is a well-posed high-multiplicity question. Calling its likely algorithm straightforward or its gain modest would not refute the mirror. No allowed objection knocks out this anchor.

The adversarial triple: the proponent anchors on up to three named results; the opponent sees that case and must defeat every anchor; the judge decides which case convinced it. These are the pipeline’s own outputs, generated by tools/triple_run.py — no human edited them. The paper’s own text is not reproduced here beyond the quoted statement above.