d4-conf-atal-2021-0180

· ? (d4-conf-atal-2021-0180)

no mirror
paperd4-conf-atal-2021-0180
authors—
venue?
filed underunclassified
judged bygpt-6-luna / xhigh (triple__luna__xhigh__c6r1)
judge confidencehigh
authors would recognise itno

Why no mirror

The paper’s numbered theorems establish axiomatic impossibilities and implications; none gives an algorithm, complexity bound, or hardness result for computing an outcome. The proposed mass-bloc question is statable, but it changes unilateral strategyproofness and still does not provide a computational anchor.

fails bit a — no named computational result to mirror

What the mirror covers

The proposed mass extension covers Theorem 2’s support-basedness, Pareto-optimality, strategyproofness, and nominator conclusion; it leaves Theorems 1 and 3 unmodeled.

Open questions for a prover

The case FOR (proponent)

The strongest honest positive case is a natural population-level extension of Theorem 2, but it does not meet the programme’s computational-anchor requirement. The paper contains no named result asserting that a problem is in P, hard, FPT, or otherwise computationally classified. Theorem 1, proved here, says that no rank-based SCF can satisfy Pareto-optimality and Kelly-strategyproofness when \(m\ge4\) and \(n\ge3\). Theorem 2, proved here, says that every support-based SCF satisfying Pareto-optimality and Kelly-strategyproofness makes every voter a nominator when \(m\ge3\). Theorem 3, proved here, says that no Kelly-strategyproof SCF can satisfy both the Condorcet loser property and non-imposition when \(m\ge3\) and \(n\ge4\). These are axiomatic results, not computational-complexity results, so none is an eligible anchor.

The most plausible continuous question suggested by Theorem 2 is this. Let \(A\) be a finite set of at least three alternatives, and let \(T\) be a finite set of weak rankings of \(A\). A society is a rational distribution \(\mu\) over \(T\), with support size \(\tau\); \(\mu_t\) is the fraction of society with ranking \(t\). Let \(F\) map such societies to nonempty choice sets, depend only on the pairwise-support vector, and be Pareto-optimal, where domination means weak preference by every positive-mass type and strict preference by some positive mass. Give strategic behavior a population-level meaning: a mass \(\delta\), where \(0<\delta\le\mu_t\), of type \(t\) may report another type \(t'\), changing the society to \(\mu-\delta e_t+\delta e_{t'}\). Require that this transfer never produce a choice set strictly Kelly-preferred by the deviating type. The question is whether, for every such \(F\) and every society \(\mu\), each occupied type \(t\) has at least one top-ranked alternative in \(F(\mu)\): \(F(\mu)\cap\operatorname{Top}(t)\ne\varnothing\).

This has a sensible high-multiplicity regime: a large electorate with many voters but relatively few distinct weak rankings. Rankings are complete types for the model, masses are population shares, and transfers describe a group of like-minded voters changing their reported ranking. The question preserves Theorem 2’s support-basedness, Pareto condition, Kelly comparison, and nominator conclusion. I would conjecture the conclusion might survive, but it needs a new proof: the transfer models a coordinated mass bloc, whereas the theorem concerns one voter at a time.

That difference is the proposal’s weakest point. In an atomless population, one person has zero mass and cannot change the outcome; giving a bloc the ability to shift positive mass changes the strategic question. More fundamentally, this mirror asks for an axiomatic theorem, with no objective or algorithmic task. It could be a worthwhile continuous-population extension of Theorem 2, but it is not a ChoCo complexity anchor, and the programme’s tractable/transferred-hardness/continuum-hardness classification does not apply to it.

The case AGAINST (opponent, writing after the proponent)

The strongest case against is that this paper offers no computational result to continuize. Theorems 1–3 establish axiomatic impossibilities and compatibility claims: they concern which social choice functions can satisfy strategyproofness, Pareto-optimality, and related properties. None classifies an algorithmic problem by complexity or gives an optimization task. So none supplies an anchor for ChoCo’s tractability, hardness-transfer, or continuum-specific-hardness landscape. Turning one into manipulation detection or a mass-robustness optimization problem would introduce a new computational question whose difficulty depends on how the rule is represented; it would not mirror a computational question in this paper.

The proposed Theorem 2 extension is the strongest candidate. A society with mass distributed over a small set of weak rankings is a sensible high-multiplicity model, and support-basedness, Pareto-optimality, and nominators all have natural mass versions. The obstacle is strategic: a single voter has zero mass, so an individual deviation leaves the society unchanged. To get a nontrivial deviation, the proposal lets a positive-mass bloc change its report. That is a coalition-manipulation axiom, rather than a continuous version of the paper’s unilateral Kelly-strategyproofness. It could be worth studying as axiomatic social choice, but it supplies no computational question for ChoCo. Requiring a coherent continuous rule across population sizes would also add a condition absent from the paper’s fixed-\(n\) theorems.

The same point applies to Theorems 1 and 3: one can replace counts by masses and ask whether their axiomatic conclusions persist, but that does not create an algorithmic result to classify. A later project might ask for the minimum mass that can manipulate a given rule. That would be a new, rule-dependent optimization problem, not a mirror anchored in this paper.

I would not claim that no continuous extension could be worthwhile anywhere in social choice. The honest negative is narrower: this paper gives no worthwhile ChoCo computational mirror to pursue. The proposed Theorem 2 extension may be mathematically sensible, but it belongs to a different research question.

The adversarial triple: the proponent anchors on up to three named results; the opponent sees that case and must defeat every anchor; the judge decides which case convinced it. These are the pipeline’s own outputs, generated by tools/triple_run.py — no human edited them. The paper’s own text is not reproduced here beyond the quoted statement above.